What are the respective concentrations (M)of Cu⁺² and Cl^- afforded by dissolving 0.200 mol CuCl₂ in water and diluting to 345 mL? A)0.200 and 0.200 B)0.580 and 1.16 C)0.200 and 0.400 D)1.16 and 2.32 E)0.580 and 0.290

Question

Quizplus · Accepted Answer

The overall reaction that occurs when 0.200 mol of CuCl is dissolved in water is: CuCl(s) + H2O(l) → Cu⁺²(aq) + Cl^-(aq) Since one mole of CuCl produces one mole of Cu⁺² and one mole of Cl^-, the concentration of each species can be calculated separately. First, calculate the total volume of the solution: V = 345 mL = 0.345 L Next, calculate the concentration of Cu⁺²: n = 0.200 mol M = n/V = 0.200 mol / 0.345 L = 0.580 M Finally, calculate the concentration of Cl^-: n = 0.200 mol M = n/V = 0.200 mol / 0.345 L = 0.580 M Therefore, the answer is B: 0.580 and 1.16.

What Are the Respective Concentrations (M)of Cu+2 and Cl- Afforded

What Are the Respective Concentrations (M)of Cu⁺² and Cl^- Afforded