What volume (L)of 0.250 M HNO₃ is required to neutralize a solution prepared by dissolving 17.5 g of NaOH in 350 mL of water? A)50.0 B)0.44 C)1.75 D)0.070 E)1.75 ×

Question

Quizplus · Accepted Answer

First, we need to determine the number of moles of NaOH present in the solution:

mass of NaOH = 17.5 g
molar mass of NaOH = 40.00 g/mol
number of moles of NaOH = 17.5 g / 40.00 g/mol = 0.4375 mol

Next, we need to determine the volume of HNO3 needed to neutralize this amount of NaOH:

mol HNO3 = mol NaOH
M HNO3 x L HNO3 = mol HNO3
0.250 M x L HNO3 = 0.4375 mol
L HNO3 = 0.4375 mol / 0.250 M
L HNO3 = 1.75 L

Therefore, the volume of 0.250 M HNO3 required to neutralize this solution is 1.75 L.

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