The molarity (M)of an aqueous solution containing 22.5 g of sucrose (C₁₂H₂₂O₁₁)in 35.5 mL of solution is __________. A)0.0657 B)1.85 × C)1.85 D)3.52 E)0.104

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of sucrose in the solution:

moles of sucrose = mass / molar mass = 22.5 g / 342.3 g/mol = 0.0656 mol

We also need to convert the volume of the solution from mL to L:

volume = 35.5 mL = 0.0355 L

Now we can calculate the molarity:

Molarity (M) = moles of solute / volume of solution in L
M = 0.0656 mol / 0.0355 L = 1.85 M

Therefore, the answer is C, 1.85.

The Molarity (M)of an Aqueous Solution Containing 22