A stock solution of HNO₃ is prepared and found to contain 13.5 M of HNO₃. If 25.0 mL of the stock solution is diluted to a final volume of 0.500 L, the concentration of the diluted solution is __________ M. A)0.270 B)1.48 C)0.675 D)675 E)270

Question

Quizplus · Accepted Answer

We can use the dilution formula:

M1V1 = M2V2

where:
M1 = initial concentration of stock solution = 13.5 M
V1 = volume of stock solution used for dilution = 25.0 mL = 0.025 L
M2 = final concentration of diluted solution
V2 = final volume of diluted solution = 0.500 L

Plugging in the values, we get:

(13.5 M)(0.025 L) = M2(0.500 L)

Solving for M2 gives:

M2 = (13.5 M)(0.025 L)/(0.500 L) = 0.675 M

Therefore, the concentration of the diluted solution is 0.675 M, which corresponds to choice C.

A Stock Solution of HNO3 Is Prepared and Found to Contain

A Stock Solution of HNO₃ Is Prepared and Found to Contain