A 22.44 g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1 °C to 39.0 °C. What is the specific heat of iron?

Question

Quizplus · Accepted Answer

The specific heat (c) can be calculated using the formula q = mcΔT, where q is the heat absorbed (180.8 J), m is the mass (22.44 g), and ΔT is the change in temperature (39.0 °C - 21.1 °C = 17.9 °C). Solving for c gives c = q / (mΔT) = 180.8 J / (22.44 g * 17.9 °C) = 0.450 J/g°C.

A 2244 G Sample of Iron Absorbs 180