The specific heat capacity of lead is 0.13 J/g-K. How much heat (in J)is required to raise the temperature of 15 g of lead from 22 °C to 37 °C?

Question

Quizplus · Accepted Answer

The formula to calculate the amount of heat required to raise the temperature of a substance can be expressed as:
Q = m * c * ΔT
where Q is the amount of heat, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Substituting the given values in the above formula, we get:
Q = 15 g * 0.13 J/g-K * (37 °C - 22 °C)
Q = 15 g * 0.13 J/g-K * 15 °C
Q = 29.25 J

Hence, the amount of heat required to raise the temperature of 15 g of lead from 22 °C to 37 °C is 29 J (option D).

The Specific Heat Capacity of Lead Is 0