In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to __________.

Question

Quizplus · Accepted Answer

The gas constant, R, is equal to 8.314 J mol^-1 K^-1. When pressure is expressed in Pascals (Pa), the units of R in the ideal gas equation PV=nRT must be adjusted to match. Since 1 Pa = 1 N/m^2 and 1 J = 1 N m, we can convert the units of R as follows: 8.314 J mol^-1 K^-1 = 8.314 N m mol^-1 K^-1 = 8.314 Pa m^3 mol^-1 K^-1. Therefore, the correct value of R to use when pressure is expressed in Pa is 8.314 Pa m^3 mol^-1 K^-1.

In Ideal Gas Equation Calculations, Expressing Pressure in Pascals (Pa)