A gas originally at 27°C and 1.00 atm pressure in a 3.9 L flask is cooled at constant pressure until the temperature is 11°C. The new volume of the gas is __________ L.
A)0.27
B)3.7
C)3.9
D)4.1
E)0.24

Question

Quizplus · Accepted Answer

According to the Charles's law, at constant pressure, the volume of a gas is directly proportional to its absolute temperature. Therefore, we can use the following equation to solve for the new volume:

(V1/T1) = (V2/T2)

where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature, respectively.

Plugging in the given values, we get:

(3.9 L / 300 K) = (V2 / 284 K)

Solving for V2, we get:

V2 = (3.9 L / 300 K) x 284 K = 3.7 L

Therefore, the new volume of the gas is 3.7 L.

The answer is B.

A Gas Originally at 27°C and 1