A sample of He gas (2.35 mol)occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.00 atm.

Name: A sample of He gas (2.35 mol)occupies 57.9 L at 300.0 K and 1.00 atm. The volume of this sample is __________ L at 423 K and 1.00 atm.
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Question

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Using Charles's Law (V1/T1 = V2/T2), where V1 = 57.9 L, T1 = 300.0 K, and T2 = 423 K, we solve for V2: V2 = V1 * (T2/T1) = 57.9 L * (423 K / 300.0 K) = 81.6 L.

A Sample of He Gas (2