The pressure exerted by 1.5 mol of gas in a 13 L flask at 22°C is __________ kPa.

Question

Quizplus · Accepted Answer

To solve this problem, we can use the ideal gas law equation, which states that:

PV = nRT

Where:
P = pressure in kPa
V = volume in L
n = number of moles of gas
R = gas constant (8.31 J/mol·K)
T = temperature in Kelvin (K)

First, we need to convert the temperature from Celsius to Kelvin by adding 273:

T = 22°C + 273 = 295 K

Next, we can rearrange the ideal gas law equation to solve for P:

P = nRT/V

Plugging in the given values, we get:

P = (1.5 mol) x (8.31 J/mol·K) x (295 K) / (13 L)

Simplifying this equation gives:

P = 280 kPa

Therefore, the answer is B) 280.

The Pressure Exerted by 1