A solution is prepared by dissolving 16.2 g of benzene (C₆H₆)in 282 g of carbon tetrachloride (CCl₄). The concentration of benzene in this solution is __________ molal. The molar masses of C₆H₆ and CCl₄ are 78.0 g/mol and 154 g/mol, respectively. A)7.36 × 10^-4 B)0.736 C)0.102 D)0.0543 E)5.43

Question

Quizplus · Accepted Answer

To find the molality, calculate the moles of benzene (16.2 g / 78.0 g/mol = 0.2077 mol) and the mass of carbon tetrachloride in kg (282 g = 0.282 kg). Molality = moles of solute / kg of solvent = 0.2077 mol / 0.282 kg = 0.736 mol/kg.

A Solution Is Prepared by Dissolving 16