Given the following reaction at equilibrium at 450.0°C: CaCO₃ (s) CaO (s) + CO₂ (g)
If pCO₂ = 0.0135 atm, K_c = __________.

Question

Given the following reaction at equilibrium at 450.0°C: CaCO₃ (s) CaO (s)+ CO₂ (g) If pCO₂ = 0.0135 atm, K_c = __________.

Quizplus · Accepted Answer

The equilibrium constant expression for the given reaction is:

Kc = [COS12]/[CaCO3]

where [COS12] is the partial pressure of COS12 in atm and [CaCO3] is the molar concentration of CaCO3 in mol/L.

At equilibrium, we are given that the reaction produces a partial pressure of COS12 of 0.0135 atm. However, we do not have any information about the concentration of CaCO3, so we cannot calculate the equilibrium constant without additional information.

Therefore, the answer is (D) 2.27 × 10-4.

Given the Following Reaction at Equilibrium at 450