At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H₂ (g) + Br₂(g) 2HBr (g)
A mixture of 0.682 mol of H₂ and 0.440 mol of Br₂ is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.556 mol of H₂ present. At equilibrium, there are __________ mol of Br₂ present in the reaction vessel.

Question

At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H₂ (g) + Br₂(g)

At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H<sub>2</sub> (g) + Br<sub>2 </sub>(g) 2HBr (g) A mixture of 0.682 mol of H<sub>2</sub> and 0.440 mol of Br<sub>2</sub> is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.556 mol of H<sub>2</sub> present. At equilibrium, there are __________ mol of Br<sub>2</sub> present in the reaction vessel. A) 0.000 B) 0.440 C) 0.556 D) 0.126 E) 0.314

2HBr (g)
A mixture of 0.682 mol of H₂ and 0.440 mol of Br₂ is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.556 mol of H₂ present. At equilibrium, there are __________ mol of Br₂ present in the reaction vessel.

Quizplus · Accepted Answer

The Answer of At elevated temperatures, molecular hydrogen and molecular bromine react to partially form hydrogen bromide: H₂ (g)+ Br₂(g) 2HBr (g) A mixture of 0.682 mol of H₂ and 0.440 mol of Br₂ is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 700 K, there are 0.556 mol of H₂ present. At equilibrium, there are __________ mol of Br₂ present in the reaction vessel.

At Elevated Temperatures, Molecular Hydrogen and Molecular Bromine React to Partially