Calculate the pOH of a solution at 25.0 °C that contains 1.94 × 10^-¹⁰ M hydronium ions.

Name: Calculate the pOH of a solution at 25.0 °C that contains 1.94 × 10 - 10 M hydronium ions.
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Question

Quizplus · Accepted Answer

pOH = -log[OH-]
pKw = pH + pOH = 14.00 (at 25°C)
[OH-] = 1.0 x 10^-14 / [H+]
[H+] = 1.94 x 10^-11 M (from given [H3O+])

[OH-] = 1.0 x 10^-14 / 1.94 x 10^-11 = 5.15 x 10^-4 M
pOH = -log(5.15 x 10^-4) = 3.29
Therefore, pOH = 4.29 (14.00 - 3.29 = 10.71)

Calculate the POH of a Solution at 25