K_b for NH₃ is 1.8 × 10^-5. What is the pOH of a 0.15 M aqueous solution of NH₄Cl at 25.0 °C?

Question

Quizplus · Accepted Answer

First, we need to find the concentration of hydroxide ions (OH-) using the given pH:
pH = 14 - pOH
pH = -log[H+] = -log(1.8 × 10-5)
pH = 4.74
Therefore, using the pH of 4.74, we can solve for the concentration of hydroxide ions:
pH + pOH = 14
4.74 + pOH = 14
pOH = 9.26
Next, we can use the concentration of hydroxide ions to find the pOH:
pOH = -log[OH-] = -log(1.22 × 10-10)
pOH = 8.96
Therefore, the answer is (C).

Kb for NH3 Is 1

K_b for NH₃ Is 1