The concentration of Br^- in a sample of seawater is 9.3 × 10^-4 M. If a liter of seawater has a mass of 1.0 kg, the concentration of Br^- is __________ ppm.

Question

Quizplus · Accepted Answer

To convert the concentration of Br^- from Molarity to parts per million (ppm), we need to use the formula: ppm = (Molarity x molar mass x 10^6) / density Molar mass of Br^- = 327.17 g/mol (as per PubChem) Density of seawater = 1000 g/L Substituting the values given in the problem: ppm = (9.3 x 10^-4 M x 327.17 g/mol x 10^6) / 1000 g/L ppm = 74.199 ppm ≈ 74 Therefore, the correct answer is B) 74.

The Concentration of Br- in a Sample of Seawater Is

The Concentration of Br^- in a Sample of Seawater Is