The value of ΔG° at 141.0°C for the formation of phosphorous trichloride from its constituent elements, P₂ (g) + 3Cl₂ (g) → 2PCl₃ (g)
Is __________ kJ/mol. At 25.0°C for this reaction, ΔH° is -720.5 kJ/mol, ΔG° is -642.9 kJ/mol, and ΔS° is -263.7 J/K.

Question

Quizplus · Accepted Answer

To find ΔG° at 141.0°C, use the equation ΔG° = ΔH° - TΔS°. Convert 141.0°C to Kelvin (414.15 K) and ΔS° to kJ (by dividing by 1000). Then, ΔG° = -720.5 kJ/mol - (414.15 K)(-0.2637 kJ/K/mol) = -612.3 kJ/mol.

The Value of ΔG° at 141