How much of the R enantiomer is present in 10 g of a mixture which has an enantiomeric excess of 60% of the R isomer?

Question

Quizplus · Accepted Answer

An enantiomeric excess of 60% means that 60% more of the mixture is the R enantiomer than the S enantiomer. This implies that in a 100% scale, 80% of the mixture is the R enantiomer and 20% is the S enantiomer (since 80% - 20% = 60% enantiomeric excess). Therefore, in 10 g of the mixture, 80% would be the R enantiomer, which is 8 g.

How Much of the R Enantiomer Is Present in 10