Using the acetoacetic ester synthesis, to produce 5-methyl-2-heptanone, the alkyl halide that should be used is 1-bromo-2-methylbutane.

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In acetoacetic ester synthesis, the alkyl halide reacts with the enolate ion of acetoacetic ester, leading to an alkylation at the alpha position. Using 1-bromo-2-methylbutane introduces a 5-carbon chain with a methyl group on the second carbon. After decarboxylation, this yields 5-methyl-2-heptanone.

Using the Acetoacetic Ester Synthesis, to Produce 5-Methyl-2-Heptanone, the Alkyl