A basketball player has made 78% of his foul shots during the season.Assuming the shots are independent,find the probability that in tonight's game he misses for the first time on his 5th attempt?

Question

Quizplus · Accepted Answer

Since the shots are independent, the probability of missing on the 5th attempt is the probability of making the first 4 shots and then missing the 5th.

The probability of making a shot is 0.78, so the probability of missing on any given attempt is 1 - 0.78 = 0.22.

Therefore, the probability of making the first 4 shots is (0.78)^4, and the probability of missing the 5th shot is 0.22.

The probability of making the first 4 shots and then missing the 5th is the product of these two probabilities:

(0.78)^4 * 0.22 = 0.0814

Therefore, the answer is B, 0.0814.

A Basketball Player Has Made 78% of His Foul Shots