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A Two-Sample Z-Test for Two Population Proportions Is to Be

Question 32

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A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
= A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
and the alternative is A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
: A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
≠ A two-sample z-test for two population proportions is to be performed using the P-value approach.The null hypothesis is : = and the alternative is : ≠ .Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value. -n<sub>1</sub> = 200 n<sub>2</sub> = 100 X<sub>1</sub> = 11 x<sub>2</sub> = 8 A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal. C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation. D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation. E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.
.Use the given sample data to find the P-value for the hypothesis test.Give an interpretation of the p-value.
-n1 = 200 n2 = 100
X1 = 11 x2 = 8


A) P-value = 0.2005;There is about a 20.05% chance that the two proportions are equal
B) P-value = 0.401;There is about a 40.1% chance that the two proportions are equal.
C) P-value = 0.401;If there is no difference in the proportions,there is about a 40.1% chance of seeing the observed difference or larger by natural sampling variation.
D) P-value = 0.2005;If there is no difference in the proportions,there is about a 20.05% chance of seeing the observed difference or larger by natural sampling variation.
E) P-value = 0.401;If there is a difference in the proportions,there is a 40.1% chance of seeing the observed difference by natural sampling variation.

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