A piece of plastic weighing 1.157 g has a volume of 1.48 cm³.A piece of wood has the same volume but weighs 3.85 g.The density of liquid X is 0.765 g/mL and the density of liquid Z is 1.13 g/mL.The two liquids are immiscible.If the plastic and wood are added to the two liquids,what is the order of layers from top to bottom in the container?

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Quizplus · Accepted Answer

The densities of the materials and liquids determine their order in the container. The plastic has a density of $ \frac{1.157 \, \text{g}}{1.48 \, \text{cm}^3} = 0.782 \, \text{g/cm}^3 $, and the wood has a density of $ \frac{3.85 \, \text{g}}{1.48 \, \text{cm}^3} = 2.60 \, \text{g/cm}^3 $. Since liquid X has a density of 0.765 g/mL, it is less dense than the plastic, making it the top layer. The plastic, being denser than liquid X but less dense than liquid Z (1.13 g/mL), will float on liquid Z. The wood, being denser than both liquids, will sink to the bottom. Thus, the order from top to bottom is liquid X, plastic, liquid Z, wood.

A Piece of Plastic Weighing 1