The smallest sample of carbon atoms that can be observed with the naked eye has a mass of approximately 2 × 10^-8 g.Given that 1 g = 6.02 × 10²³ amu,and that carbon has an atomic weight of 12.01 amu,determine the number of carbon atoms present in the sample. A)1 × 10¹⁵ B)1 × 10¹⁶ C)1 × 10¹⁷ D)6 × 10²³

Question

The smallest sample of carbon atoms that can be observed with the naked eye has a mass of approximately 2 × 10^-8 g.Given that 1 g = 6.02 × 10²³ amu,and that carbon has an atomic weight of 12.01 amu,determine the number of carbon atoms present in the sample. A)1 × 10¹⁵ B)1 × 10¹⁶ C)1 × 10¹⁷ D)6 × 10²³

Quizplus · Accepted Answer

First, convert the mass of the sample from grams to amu: 2 × 10^-8 g * (6.02 × 10^23 amu/g) = 1.204 × 10^16 amu. Then, divide by the atomic weight of carbon (12.01 amu) to find the number of atoms: 1.204 × 10^16 amu / 12.01 amu/atom ≈ 1 × 10^15 atoms.

The Smallest Sample of Carbon Atoms That Can Be Observed