How many grams of calcium chloride are needed to produce 10.0 g of potassium chloride? CaCl₂(aq)+ K₂CO₃(aq)→ 2 KCl(aq)+ CaCO₃(aq) A)0.134 g B)7.44 g C)9.28 g D)18.56 g

Question

Quizplus · Accepted Answer

The balanced equation shows that 1 mole of calcium chloride produces 2 moles of potassium chloride. To find the amount of calcium chloride needed to produce 10.0 g of potassium chloride, we need to determine the moles of potassium chloride produced.

Using the molar mass of potassium chloride (74.55 g/mol), we can calculate the number of moles:

10.0 g KCl ÷ 74.55 g/mol = 0.134 moles KCl

Since 1 mole of calcium chloride produces 2 moles of potassium chloride, we need half that amount of calcium chloride:

0.134 moles KCl ÷ 2 = 0.067 moles CaCl2

Using the molar mass of calcium chloride (110.98 g/mol), we can convert this to grams:

0.067 moles CaCl2 × 110.98 g/mol = 9.28 g CaCl2

Therefore, the answer is C: 9.28 g.

How Many Grams of Calcium Chloride Are Needed to Produce