When iron(III)oxide reacts with hydrochloric acid,iron(III)chloride and water are formed.How many grams of iron(III)chloride are formed from 10.0 g of iron(III)oxide and 10.0 g of hydrochloric acid?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:

Fe2O3 + 6HCl → 2FeCl3 + 3H2O

Using the molar masses and stoichiometry of the equation, we can determine the limiting reactant and the amount of product formed:

- The moles of Fe2O3 are:

10.0 g / 159.69 g/mol = 0.0626 mol

- The moles of HCl are:

10.0 g / 36.46 g/mol = 0.2744 mol

- The amount of product formed by the limiting reactant (Fe2O3) is:

0.0626 mol × (2 mol FeCl3 / 1 mol Fe2O3) × (162.2 g/mol FeCl3) = 20.3 g

Therefore, the answer is (B) 14.8 g.

When Iron(III)oxide Reacts with Hydrochloric Acid,iron(III)chloride and Water Are Formed