How many Fe(II)ions are there in 5.00 g of FeSO₄?

Question

Quizplus · Accepted Answer

To find the number of Fe(II) ions in 5.00 g of FeSO₄, first calculate the molar mass of FeSO₄, which is approximately 151.9 g/mol. Then, determine the number of moles of FeSO₄ in 5.00 g: 5.00 g / 151.9 g/mol = 0.0329 mol. Since each mole of FeSO₄ contains one mole of Fe(II) ions, there are 0.0329 mol of Fe(II) ions. Multiply by Avogadro's number (6.022 × 10²³ ions/mol) to find the number of ions: 0.0329 mol × 6.022 × 10²³ ions/mol = 1.98 × 10²² ions.

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