How many moles of BCl₃ are needed to produce 15.0 g of HCl(aq)in the following reaction? BCl₃(g)+ 3 H₂O(l)→ 3 HCl(aq)+ B(OH)₃(aq) A)0.137 mol B)0.411 mol C)1.23 mol D)7.29 mol

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First, calculate the molar mass of HCl, which is approximately 1 (H) + 35.5 (Cl) = 36.5 g/mol. To find out how many moles of HCl are in 15.0 g, divide the mass by the molar mass: 15.0 g / 36.5 g/mol = 0.411 mol of HCl. Since the reaction shows that 1 mole of BCl₃ produces 3 moles of HCl, the moles of BCl₃ needed for 0.411 moles of HCl is 0.411 mol HCl * (1 mol BCl₃ / 3 mol HCl) = 0.137 mol BCl₃.

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How Many Moles of BCl₃ Are Needed to Produce 15