How many chloride ions are in 1.50 mol of aluminum chloride?

Question

Quizplus · Accepted Answer

Aluminum chloride (AlCl3) has a formula indicating one aluminum ion (Al3+) for every three chloride ions (Cl-). Therefore, for every mole of AlCl3, there are 3 moles of chloride ions. Given 1.50 moles of AlCl3, the total moles of chloride ions would be 1.50 * 3 = 4.50 moles. Since 1 mole of any substance contains Avogadro's number of entities (approximately 6.022 × 10^23), 4.50 moles of chloride ions would contain 4.50 * 6.022 × 10^23 = 2.71 × 10^24 chloride ions.

How Many Chloride Ions Are in 1