When 14.0 g of calcium metal is reacted with water,5.00 g of calcium hydroxide is produced.Using the following balanced equation,calculate the percent yield for the reaction? Ca(s)+ 2 H₂O(l)→ Ca(OH)₂(aq)+ H₂(g)

Question

Quizplus · Accepted Answer

Step 1: Calculate the theoretical yield of calcium hydroxide:

Moles of Ca = mass/Molar mass = 14.0 g/40.08 g/mol = 0.349 mol

Moles of Ca(OH)2 = 0.349 mol/1 = 0.349 mol

Mass of Ca(OH)2 = moles × molar mass = 0.349 mol × (74.09 + 2(15.999)) g/mol = 26.56 g

Step 2: Calculate the percent yield:

% yield = (actual yield/theoretical yield) × 100%

actual yield = 5.00 g

theoretical yield = 26.56 g

% yield = (5.00 g/26.56 g) × 100% = 18.8%

Therefore, the closest answer is B) 19.3% (rounded to one decimal place).

When 140 G of Calcium Metal Is Reacted with Water,5