When 1.00 × 10²² molecules of ammonia react with 7.00 × 10²² molecules of oxygen according to the chemical equation shown below,how many grams of nitrogen gas are produced? 4 NH₃(g)+ 3 O₂(g)→ 2 N₂(g)+ 6 H₂O(g) A)0.232 g B)2.17 g C)0.464 g D)1.86 g

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Quizplus · Accepted Answer

1.00 × 10²² molecules of ammonia react with 7.00 × 10²² molecules of oxygen, which is the limiting reactant. Therefore, 1.00 × 10²² molecules of nitrogen gas are produced. The molar mass of nitrogen gas is 28.01 g/mol. Therefore, the mass of nitrogen gas produced is 1.00 × 10²² molecules × (28.01 g/mol) / (6.022 × 10²³ molecules/mol) = 0.464 g.

When 100 × 1022 Molecules of Ammonia React with 7

When 100 × 10²² Molecules of Ammonia React with 7