What is the first ionization energy for a hydrogen atom in the ground state? The Rydberg constant is . A)7.27 × 10^-36 J B)1.63 × 10^-27 J C)2.18 × 10^-18 J D)0.00823 J

Question

Quizplus · Accepted Answer

The first ionization energy of a hydrogen atom can be calculated using the expression:
IE1 = -RH/n^2
Where RH is the Rydberg constant, n is the principal quantum number of the excited state, and IE1 is the ionization energy.
For a hydrogen atom in the ground state (n=1), the ionization energy is:
IE1 = -RH/n^2 = -11.0 x 10^6 m^-1
To convert this to joules, we multiply by the Planck constant (h) and the speed of light (c):
IE1= -11.0 x 10^6 m^-1 x h x c = 2.18 x 10^-18 J
Therefore, the correct answer is C) 2.18 × 10^-18 J.

What Is the First Ionization Energy for a Hydrogen Atom