The dipole moment of ClF is 0.88 D,and its bond length is 163 pm.What is the percent ionic character of the Cl-F bond?
A)0.54%
B)7.8%
C)11%
D)25%

Question

Quizplus · Accepted Answer

The percent ionic character of a bond can be calculated using the following formula:
%Ionic character = 100 x (1 - e^(-ΔX/4.0))
where ΔX is the electronegativity difference between the two atoms in the bond.
For ClF, ΔX = |3.16 - 3.98| = 0.82
Substituting this value in the formula, we get:
%Ionic character = 100 x (1 - e^(-0.82/4.0)) = 11%

Therefore, the correct answer is (C) 11%.

The Dipole Moment of ClF Is 0