For the reaction I₂(g)→ I₂(s),ΔH° = -62.4 kJ at 25°C.Based on these data,at 25°C

Question

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According to the given reaction, the substance I₂ is going from a gas state to a solid state, which is the process of sublimation. The given ΔH° value (-62.4 kJ) represents the enthalpy change for this process. Thus, ΔH°_sub = -62.4 kJ/mol. Option D correctly represents this value with a positive sign. Option A is incorrect as the sign of ΔH°_vap should be positive for vaporization, but here the given reaction is for sublimation.

For the Reaction I2(g)→ I2(s),ΔH° = -62

For the Reaction I₂(g)→ I₂(s),ΔH° = -62