It takes 15.5 kJ of energy to raise the temperature of 200 g of benzene from 25.0°C to 70.0°C.What is the specific heat of benzene?

Question

Quizplus · Accepted Answer

The specific heat (c) formula is:

q = mcΔT

where q is the heat absorbed, m is the mass of the substance, ΔT is the change in temperature and c is the specific heat.

Plugging in the given values, we get:

15.5 kJ = (200 g)(c)(70.0°C - 25.0°C)

15.5 kJ = (200 g)(c)(45.0°C)

c = 1.72 J/(g ∙ °C)

Therefore, the specific heat of benzene is 1.72 J/(g ∙ °C). Option B is the correct choice.

It Takes 15