It takes 11.2 kJ of energy to raise the temperature of 145 g of benzene from 22.0°C to 67.0°C.What is the specific heat of benzene?

Question

Quizplus · Accepted Answer

Use the formula:
q = mCΔT
where q = 11.2 kJ = 11,200 J
m = 145 g
ΔT = (67.0°C - 22.0°C) = 45.0°C

Solving for C:
C = q/(mΔT) = (11,200 J)/(145 g x 45.0°C) = 1.72 J/(g ∙ °C)

Therefore, the specific heat of benzene is 1.72 J/(g ∙ °C), which is closest to choice B.

It Takes 11