A 55.0-L steel tank at 20.0°C contains acetylene gas,C₂H₂,at a pressure of 1.39 atm.Assuming ideal behavior,how many grams of acetylene are in the tank? A)3.17 g B)8.20 g C)82.9 g D)1210 g

Question

Quizplus · Accepted Answer

Using the ideal gas law equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature, we can solve for the number of moles of acetylene.

n = PV/RT = (1.39 atm)(55.0 L)/(0.0821 L*atm/mol*K)(293 K) = 2.968 mol

To find the mass of acetylene, we need to use the molar mass of acetylene.

C2H2: (2 x 12.01 g/mol) + (2 x 1.01 g/mol) = 26.04 g/mol

mass = n x molar mass = 2.968 mol x 26.04 g/mol = 77.0 g

Therefore, the answer is C) 82.9 g.

A 550-L Steel Tank at 20