When 12.0 g of zinc metal reacts with excess HCl,how many liters of H₂ gas are produced at STP? A)0.243 L B)0.486 L C)4.11 L D)8.23 L

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Quizplus · Accepted Answer

The reaction between zinc metal and hydrochloric acid (HCl) can be represented by the equation: Zn + 2HCl → ZnCl2 + H2. The molar mass of zinc (Zn) is approximately 65.38 g/mol. Given 12.0 g of Zn, the moles of Zn are calculated as 12.0 g / 65.38 g/mol ≈ 0.1835 mol. According to the stoichiometry of the reaction, 1 mole of Zn produces 1 mole of H2 gas. Therefore, 0.1835 mol of Zn will produce 0.1835 mol of H2 gas. At STP (Standard Temperature and Pressure), 1 mole of any gas occupies 22.4 liters. Thus, the volume of H2 gas produced is 0.1835 mol × 22.4 L/mol ≈ 4.11 L.

When 120 G of Zinc Metal Reacts with Excess HCl,how Many