Bromine is one of only two elements that is a liquid at room temperature.Bromine has a heat of vaporization of 30.91 kJ/mol and its boiling point is 59°C.What is the entropy of vaporization for bromine?
A)-301 J/(mol ∙ K)
B)-93.1 J/(mol ∙ K)
C)10.7 J/(mol ∙ K)
D)93.1 J/(mol ∙ K)

Question

Quizplus · Accepted Answer

The entropy of vaporization ($\Delta S_{vap}$) can be calculated using the formula $\Delta S_{vap} = \frac{\Delta H_{vap}}{T_{b}}$, where $\Delta H_{vap}$ is the heat of vaporization and $T_{b}$ is the boiling point in Kelvin. First, convert the boiling point from Celsius to Kelvin: $59°C + 273.15 = 332.15 K$. Then, plug the values into the formula: $\Delta S_{vap} = \frac{30.91 \times 10^3 J/mol}{332.15 K} = 93.1 J/(mol \cdot K)$.

Bromine Is One of Only Two Elements That Is a Liquid