A kitchen pressure cooker operates at 1.70 atm.The ΔH_vap of water is 40.7 kJ/mol.What is the boiling point of water in the pressure cooker?

Question

Quizplus · Accepted Answer

The boiling point of water in a pressure cooker can be found using the following equation:
ΔHSvap = Rln(P2/P1)
where ΔHSvap is the enthalpy of vaporization of water, R is the gas constant, P1 is the standard atmospheric pressure (1 atm), and P2 is the pressure inside the pressure cooker.

We can rearrange this equation to solve for the boiling point (T2) as follows:
T2 = (ΔHSvap/R) * (ln(P2/P1))^-1 + T1
where T1 is the boiling point of water at 1 atm (373 K).

Plugging in the given values, we get:
T2 = (40.7 kJ/mol / 8.314 J/mol*K) * (ln(1.70/1))^(-1) + 373 K
T2 = 388.6 K

Rounding to the nearest whole number, the boiling point of water in the pressure cooker is 389 K, which corresponds to choice C.

A Kitchen Pressure Cooker Operates at 1