A solution is prepared by dissolving 171 g of CdCl₂ in enough water to make exactly 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the weight percent of CdCl₂ in the solution? A)7.17% B)44.0% C)56.0% D)68.4%

Question

Quizplus · Accepted Answer

First, we need to find the total mass of the solution. Since the volume is 250.0 mL and the density is 1.556 g/mL, the total mass of the solution is 250.0 mL * 1.556 g/mL = 389 g. The mass of CdCl2 in the solution is given as 171 g. To find the weight percent of CdCl2 in the solution, we use the formula: (mass of solute / total mass of solution) * 100. Therefore, (171 g / 389 g) * 100 = 43.96%, which rounds to 44.0%.

A Solution Is Prepared by Dissolving 171 G of CdCl2

A Solution Is Prepared by Dissolving 171 G of CdCl₂