The Henry's Law constant of methyl bromide,CH₃Br,is k = 0.159 mol/(L ∙ atm)at 25°C.What is the solubility of methyl bromide in water at 25°C and at a partial pressure of 290.mm Hg?

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Henry's Law states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the liquid. The formula is S = kP, where S is the solubility, k is the Henry's Law constant, and P is the pressure. Given k = 0.159 mol/(L∙atm) and a pressure of 290 mm Hg, which is 290/760 atm (since 1 atm = 760 mm Hg), the solubility S = 0.159 mol/(L∙atm) * (290/760) atm = 0.0607 mol/L.

The Henry's Law Constant of Methyl Bromide,CH3Br,is K = 0

The Henry's Law Constant of Methyl Bromide,CH₃Br,is K = 0