Methanol can be produced by the following reaction: CO(g) + 2 H₂(g) → CH₃OH(g) .
How is the rate of disappearance of hydrogen gas related to the rate of appearance of methanol?
- = ?

Question

Methanol can be produced by the following reaction: CO(g)+ 2 H₂(g)→ CH₃OH(g). How is the rate of disappearance of hydrogen gas related to the rate of appearance of methanol? - = ?

Quizplus · Accepted Answer

According to the balanced chemical equation, for every 2 moles of hydrogen gas consumed, 1 mole of methanol is produced. Therefore, the rate of disappearances of hydrogen gas is directly related to the rate of appearance of methanol, but in a 2:1 ratio. So, the answer is C, which represents that the rate of disappearance of hydrogen gas is 2 times greater than the rate of appearance of methanol.

Methanol Can Be Produced by the Following Reaction: CO(g)+ 2