The following pictures represent the initial state and the equilibrium state for the gaseous state reaction of A 2 molecules (shaded spheres)with B atoms (unshaded spheres)to give AB molecules.
-If the volume of the equilibrium mixture is decreased,what will happen to the number of AB molecules and the number of B atoms?

Question

The following pictures represent the initial state and the equilibrium state for the gaseous state reaction of A 2 molecules (shaded spheres)with B atoms (unshaded spheres)to give AB molecules. 
-If the volume of the equilibrium mixture is decreased,what will happen to the number of AB molecules and the number of B atoms?

Quizplus · Accepted Answer

According to Le Chatelier's principle, when the volume is decreased, the equilibrium will shift in the direction that produces fewer moles of gas. In this case, the formation of AB molecules produces fewer moles of gas than the reactant A₂ molecules and B atoms. Therefore, the equilibrium will shift towards the formation of more AB molecules, resulting in an increase in the number of AB molecules. At the same time, the decrease in volume will increase the concentration of B atoms, driving the equilibrium to consume more B atoms to form AB molecules, resulting in a decrease in the number of B atoms.

The Following Pictures Represent the Initial State and the Equilibrium