The decomposition of ammonia is: 2 NH₃(g)= N₂(g)+ 3 H₂(g).If K_p is 1.5 × 10³ at 400°C,what is the partial pressure of ammonia at equilibrium when N₂ is 0.40 atm and H₂ is 0.15 atm?

Question

Quizplus · Accepted Answer

Using the equilibrium expression: K_p = (PH₂)3(PN₂) / (PNH₃)2 Substituting the values, we get: 1.5 × 10³ = (0.15)3(0.40) / (PNH₃)2 PNH₃ = 9.5 × 10^-4 atm

The Decomposition of Ammonia Is: 2 NH3(g)= N2(g)+ 3 H2(g)

The Decomposition of Ammonia Is: 2 NH₃(g)= N₂(g)+ 3 H₂(g)