From the following chemical reactions determine the relative Br∅nsted-Lowry acid strengths (strongest to weakest) . HClO₄(aq) + H₂O(l) → H₃O⁺(aq) + ClO₄^-(aq)
HNO₂(aq) + H₂O(l) ⇌ H₃O⁺(aq) + NO₂^-(aq)

Question

From the following chemical reactions determine the relative Br∅nsted-Lowry acid strengths (strongest to weakest). HClO₄(aq)+ H₂O(l)→ H₃O⁺(aq)+ ClO₄^-(aq) HNO₂(aq)+ H₂O(l)⇌ H₃O⁺(aq)+ NO₂^-(aq) A)HClO₄ > H₃O⁺ > HNO₂ B)HClO₄ > HNO₂ > H₃O⁺ C)H₃O⁺ > HClO₄ > HNO₂ D)H₃O⁺ > HNO₂ > HClO₄

Quizplus · Accepted Answer

The stronger the acid, the weaker its conjugate base. The conjugate base of HClO₄ is ClO₄^-, the conjugate base of H₃O⁺ is H₂O, and the conjugate base of HNO₂ is NO₂^-. Of these three conjugate bases, ClO₄^- is the weakest base, so HClO₄ is the strongest acid. H₂O is a stronger base than ClO₄^-, so H₃O⁺ is a weaker acid than HClO₄. NO₂^- is a stronger base than H₂O, so HNO₂ is a weaker acid than H₃O⁺. Therefore, the relative Brønsted-Lowry acid strengths are HClO₄ > H₃O⁺ > HNO₂.

From the Following Chemical Reactions Determine the Relative Br∅nsted-Lowry Acid