Methylamine CH₃NH₂,has a base dissociation constant of 3.7 × 10^-4.What is the conjugate acid of methylamine and what is its acid dissociation constant? A)CH₃NH₃⁺,2.7 × 10³ B)CH₃NH₃⁺,3.7 × 10^-4 C)CH₃NH₃⁺,2.7 × 10^-11 D)CH₃NH₂^-,2.7 × 10^-11

Question

Quizplus · Accepted Answer

The conjugate acid of methylamine (CH3NH2) is formed by adding a proton (H+), resulting in CH3NH3+. The acid dissociation constant (Ka) for the conjugate acid can be found using the relationship Kw = Ka * Kb, where Kw is the ion product of water (1.0 × 10^-14 at 25°C). Given that the base dissociation constant (Kb) for methylamine is 3.7 × 10^-4, we can calculate Ka as (1.0 × 10^-14) / (3.7 × 10^-4) = 2.7 × 10^-11.

Methylamine CH3NH2,has a Base Dissociation Constant of 3

Methylamine CH₃NH₂,has a Base Dissociation Constant of 3