What is the relationship between K_a and K_b at 25°C for a conjugate acid base pair? A)K_a × K_b = 1 × 10^-14 B)K_a/K_b = 1 × 10^-14 C)K_b/K_a = 1 × 10^-14 D)K_a - K_b = 1 × 10^-14

Question

Quizplus · Accepted Answer

The product of the dissociation constants (Ka for the acid and Kb for the base) of a conjugate acid-base pair is equal to the ion product of water (Kw), which is 1 × 10^-14 at 25°C.

What Is the Relationship Between Ka and Kb at 25°C

What Is the Relationship Between K_a and K_b at 25°C