What is the resulting pH when 0.005 moles of KOH is added to 0.100 L of a buffer solution that is 0.100 M in H2PO4- and 0.100 M HPO42- and the Ka2 = 6.2 × 10-8?
A) 5.21
B) 5.61
C) 6.73
D) 7.69
Correct Answer:
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