Without doing any calculations,determine whether the standard entropy change,ΔS° is positive or negative for each of the following reactions. reaction 1: C(graphite) + O₂(g) → CO₂(g)
Reaction 2: 2 CO(g) + O₂(g) → 2 CO₂(g)

Question

Quizplus · Accepted Answer

For reaction 1, the standard entropy change is likely positive because a solid (C(graphite)) and a gas (O₂) are reacting to form a gas (CO₂), which has more disorder than the reactants. For reaction 2, the standard entropy change is likely negative because two gases (CO and O₂) are reacting to form a gas (CO₂), which has less disorder than the reactants. The fact that there are twice as many moles of products as reactants does not necessarily mean that the standard entropy change will be positive; the nature of the reactants and products also matters.

Without Doing Any Calculations,determine Whether the Standard Entropy Change,ΔS° Is