For the reaction 3 C₂H₂(g)→ C₆H₆(l)at 25°C,the standard enthalpy change is -631 kJ and the standard entropy change is -430 J/K.Calculate the standard free energy change at 25°C?

Question

Quizplus · Accepted Answer

The standard free energy change ($\Delta G^\circ$) can be calculated using the formula $\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ$, where $\Delta H^\circ$ is the standard enthalpy change, $T$ is the temperature in Kelvin, and $\Delta S^\circ$ is the standard entropy change. Given $\Delta H^\circ = -631$ kJ and $\Delta S^\circ = -430$ J/K (or -0.430 kJ/K) at $T = 25°C$ (or 298 K), $\Delta G^\circ = -631\, \text{kJ} - (298\, \text{K})(-0.430\, \text{kJ/K}) = -631\, \text{kJ} + 128\, \text{kJ} = -503\, \text{kJ}$.

For the Reaction 3 C2H2(g)→ C6H6(l)at 25°C,the Standard Enthalpy Change

For the Reaction 3 C₂H₂(g)→ C₆H₆(l)at 25°C,the Standard Enthalpy Change